Write a function to get Nth node in a Linked List

Write a function to get Nth node in Linked List.The prototype of the getNth_node() is as follows:

void getNth_node(int N)
{
};

This function will take N as an argument and display the content of the node at index N (1<=N<=len) ,where len is the length of the Linked List.

Solution:

/*
Problem Description
write a function to get Nth node in a linked list\

submitted by
Arjun Mishra
*/
#include<iostream>
#include<stdlib.h>
using namespace std;

struct node
{
       int data;
       struct node* next;
       }*head,*tail,*temp;
      
int count=0,len=0;

void push(int val)
{
     temp=(struct node*)malloc(sizeof(struct node));
     if(!(temp))
     {
                cout<<"Problem in creating Node!\n";
                return;
                }
     ::len++;
     temp->data=val;
     temp->next=NULL;
     if(head==NULL)
     {
                   head=temp;
                   tail=temp;
     }
     else
     {
                   tail->next=temp;
                   tail=temp;                 
     }
     }
void traverse()
{
     if(head==NULL)
     cout<<"List is Empty\n";
     else
     {
          temp=head;
          while(temp!=NULL)
          {
          cout<<temp->data<<"->";
          temp=temp->next;
          }
          cout<<"NULL"<<endl;
          }
     }
void getNth_node(int N)
{
     temp=head;
     while(temp!=NULL)
     {
      ::count++;
      if(::count==N)
      {
       cout<<"The value at node is:"<<temp->data<<endl;
       break;          
       }               
       temp=temp->next;
                      }
     }    
int main()
{
    int N;
    push(23);
    push(4);
    push(7);
    push(8);
    push(10);
    push(18);
    cout<<"The list is as follows\n";
    traverse();
    cout<<"Enter the value of N\n";
    cin>>N;
    if((::len)<(N))
    cout<<"No such node exists\n";
    else
    getNth_node(N);
    return 0;
    }